If you could give me an equation that would be great, trying effectively to calculate the size of a counterbalance needed to keep a weight on the end of a lever level. thanks!
A 15 ft massless lever? What's that? A hologram? Program your hologram projector to project the weight at a certain place in the room.
force * distance = constant. I can't quite see the arrangement you're describing, but the force*distance you need will be the same as 200*15 = 3000, if the 200lb is at the free end of the lever. If it's at the pivot end then the distance will be a lot smaller and the force at a distance of 15ft will be less. Edit the only basic is moments = force x distance. Shoulders are complicated. Imagine a see saw in a playground. For the see saw to be level the force x distance on each side must be the same. If you are with a small child and the child is at the end of the see saw then you need to sit closer to the center for the moments to balance.
