A foundry worker places a 5.78 kg sheet of copper at a temperature of 17°C on top of a 16.8 kg sheet of silver at 65°C. Assume no heat is lost to the surroundings.
The heat energy that is gained by the copper is equal to the heat energy that is given off by the silver. The following specific heats are from a table in my physic’s book. Copper 387 J Silver 234 For copper, Q 5.78 * 387 * (Tf – 17) 2,236.86 * Tf – 38,026.62 For silver, Q 16.8 * 234 * (65 – Tf) 255,528 – 3,931.2 * Tf 2,236.86 * Tf – 38,026.62 255,528 – 3,931.2 * Tf 6,168.06 * Tf 293.554.62 Tf 293,554.62 ÷ 6,168.06 The final temperature is approximately 47.6?C.
The heat energy that is gained by the copper is equal to the heat energy that is given off by the silver. The following specific heats are from a table in my physic’s book. Copper 387 J Silver 234 For copper, Q 5.78 * 387 * (Tf – 17) 2,236.86 * Tf – 38,026.62 For silver, Q 16.8 * 234 * (65 – Tf) 255,528 – 3,931.2 * Tf 2,236.86 * Tf – 38,026.62 255,528 – 3,931.2 * Tf 6,168.06 * Tf 293.554.62 Tf 293,554.62 ÷ 6,168.06 The final temperature is approximately 47.6?C.
