A square hole 6.4 cm along each side is cutin a sheet of copper.Calculate the change in the area of this holeif the temperature of the sheet is increased by77 K. The coe?cient of linear expansion ofcopper is 1.7 × 10^?5(?C)^?1.Answer in units of cm^2
The Kelvin and Celsius temperature scales differ only by a constant, so we can also say that the temperature of the sheet is increased by 77°C. Thus, each side of the square hole increases in length by a factor of [1.7 × 10^?5(°C)^?1]*77°C approx. 1.31 x 10^-3 The length of each side becomes approx. 6.4 x (1 + 1.31 x 10^-3) approx. 6.4 x 1.00131 cm The change in area approx. (6.4 x 1.00131)^2 - 6.4^2 approx. 41.07 - 40.96 approx. 0.11 cm^2
If I comprehend what you're asking, section would not replace no remember how many cases you chop back it. each and everything jointly nevertheless equivalent the unique section. Perimeter is the only element that ought to alter.
