An inductor of 0.5 H and a resistance of 1.2 K ohms are connected in series with an ideal source with e.m.f. 6 V. The current expression in the circuit as a function of time is: 5.0*10^-3(1-e^-2398t ) . Calculate the potential difference across the inductor at t 0.417 ms. the correct answer is: 2.21v . can you tell me how to do it? :)
Set t 0.417*10^-3 in the formula given. That gives you the current at t 0.417 ms ie 3.16*10^-3 ma In the 1.2k resistor, that drops v i*r 1.2*10^3*3.16*10^-3 volts ie 3.79 volts That leaves (6 - 3.79) volts ie 2.21 volts across the inductor.
