I came across a probability problem and am having trouble coming up with the answer. There are 9 people in a group and 9 chairs to sit in. If 3 of them are girls and 3 chairs are pink, what are the chances that the 3 girls sit in the 3 pink chairs? Assuming everything is perfectly random and each person has the same probability to sit in any of the 9 chairs. Thanks!
There are 9! possible arrangements. There are 3 ways a girl can sit in the first pink chair, 2 ways for the second and 1 way for the third; 6 ways for a boy to sit in the first non-pink chair then 5,4,3,2,1 So P(3 girls in pink) = (3?2?1?6?5?4?3?2?1) / (9?8?7?6?5?4?3?2?1) = (3?2?1)/(9?8?7) = 1 / (3?4?7) = 1/84 That's my guess anyway
p (pink chair) 3/9 p (girls) 3/9 P (girls pink chair) 6/9 i took my statistics final today and i am probably pulling this out of nowhere but maybe this is it lol
