Hello I was wondering if someone could help me solve this problem. My study guide gives answers but no methods.2 hydrocarbon streams pass through a cross flow heat exchanger. The first is 150000kg/hr of pure n-hexadecane (Cp=2.2J/g-K). This is being warmed from 293K to 330K. The second stream is 129000kg/hr of 33wt% n-dotriacontane and 67% tetraphenylethelyne (Cp=2.2J/g-K). The tubing is 0.05m inner diameter and 0.06m outer diameter. How can I find area and total length of tubing required? Also, how do I reason the heat transfer coefficient? My professor gave us the 5 basic ones (gas-gas, gas-liquid, water-liquid, condenser, reboiler)
Many compressor aftercoolers are quite small shell and tube heat exchangers and use water as the least expensive and most easily available coolant. Some are simply double pipe type exchangers (very inexpensive) with a length of small diameter pipe inside a larger diameter pipe, using simple pipe coupling connectors, and they also can use just water as the coolant.
For the detailed step to calculate/design of heat exchangers you may refer to Coulson Richardson's Chemical Engineering, vol 6..there's a complete algorithm on how to design a heat exchanger. one of the methods used in this book is Kern method. overall heat transfer coefficient usually are typical values and based on experiences using the same fluids. The typical values of heat transfer coefficient usually refers to the best heat transfer coefficient that could result in the minimum heat transfer area needed, which in turn could result to a cheaper heat exchanger.
this is the complete book of chemical engineering coulson and richardson’s vol 2. All the application of chemical engineering, complete problems of chemical engineering in coulson and Richardson vol 2.
