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Chemistry Test tube mystery?

We are doing a 12 test tube mystery in chem and we have bottles of the solutions and we are given the names on a sheet of paper. So how are we supposed to correlate the bottles to the name of the solution?Like solubility, color, odor, and stuff i just need an explaniation how to do it for each one.The names arealuminum chloridesodium hydroxidehydrochloric acidpotassium chromatesodium carbonatecopper (II) sulfatesilver nitrateammonialead (II) nitrateferric nitratesodium acetatenickel chloride

Answer:

Aluminium chloride white or pale yellow solid Sodium hydroxide White solid Hydrochloric acid clear/ light yellowy liquid. Strong smell. Potassium chromate yellow odourless powder. Sodium carbonate White solid(similar to alluminium chloride but will be clearly white) Copper (II) sulfate Blue liquid. Silver nitrate white powder. Soluble in ethanol and acetone Lead(II) nitrate white crystals Ferric nitrate pale violet crystals Sodium acetate white odourless powder nickel chloride yellow green crystals
it depends since Iron is atransitional element it can either Iron(II0 or Iron(IiI) since your above example says Iron(Ii0 it will later oxodise to give Iron(IiI0 increase in nuclear charge
Atoms with a natural charge want to become neutral. Iron atoms are naturally at either 2+ or 3+. Since chloride has a 2- charge and hydrogen has a 1- charge, iron (II) or iron 2- is combined with chloride to become neutral. It uses a type of reaction called single replacement.
For the best answers, search on this site shorturl.im/awRl5 This is a bit of an odd question. Basically you want to classify all your chemicals as either being solid, liquid, gaseous or aqueous. Aqueous means that it is in solution. 1) This one involves using gaseous hydrogen chloride which reacts with solid iron to form solid iron(II) chloride and hydrogen gas (anhydrous means without water). Fe(s) + 2HCL(g) FeCl2(s) + H2(g) 2) Here we have solid iron being dissolved in a solution of hydrochloric acid (which is basically the hydrogen chloride gas dissolved in water). Here we see that the iron starts solid and is reacted with the aqueous hydrogen chloride/ hydrochloric acid to form a solution of iron(II) chloride. Fe(s) + 2HCL(aq) FeCl2(aq) + H2(g) 3) This is basically the same as number two, except with the solution of iron(II) chloride, we evaporate the water which leaves some in the crystal structure of the solid iron(II) chloride-4-water. Note that you write water as being a liquid and not being aqueous. 4H2O(l) + FeCl2(aq) 4H2O.FeCl2(s) I hope this is what you need and it helps.
Sodium Carbonate + Hydrochloric Acid Sodium chloride + water + carbon dioxide. Remember all CARBONATES react with all ACIDS to release the corresponding salt plus water plus carbon dioxide. The general equation is Carbonate + Acid Salt + Water + Carbon Dioxide. Na2CO3(s) + 2HCl(aq) 2NaCl(aq) + H2O(l) + CO2(g) The bubbling (effervescence) is the release of carbon dioxide. To test for carbon dioxide. Pass (bubble) the gas through limewater, which will turn 'milky'. This is the classic test for carbon dioxide (CO2). For copper sulphate and sodium carbonate The reaction scheme is below. Notice it releases carbon dioxide (CO2) - the effervescence. As previously CO2 is bubbled through limewater which turn from clear (Transparent) to 'milky' white. 2 CuSO4 + 2 Na2CO3 + H2O → Cu2(OH)2CO3 + 2 Na2SO4 + CO2

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