A 3.9 H inductor is in parallel with a 67Ω resistor. The inductor current is 7.6 A at t 0 . Find: (a) iL(0.8ms)If another 67Ω resistor is connected in parallel with the inductor at t 1 ms, find: (b) iL(2ms)
a) I inductor 7.6(e^(-t/τ)) where τ L/R 3.9 H/ 67Ω 58 milliseconds At 0.8 milliseconds, I inductor 7.6(e^-(0.8/58)) 7.496 Amps b) at 1 milliseconds, I inductor 7.6(e^-(1/5.8)) 7.47 amps the new time constant is τ L/R 3.9 H/ 33.5Ω 116 milliseconds since R is now 67||67 33.5Ω I inductor 7.47(e^-((t-1 ms)/τ)) at 2 mS, I inductor 7.47(e^-((2-1)/116) 7.47(e^-(1/116)) 7.41 amps
