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Question:

connecting different cnc machines to a Ethernet network?

dear friendi want to connect many and different cnc machines to a Ethernets lan although all of them have rs 232 port if any one here can help me with that what kind of hardware and software i will need for it.

Answer:

You need a routerSwitches are layer 1 and have nothing to do with layer 3You can use a switch once it is hooked to a router to extend to multiple clients or you could also use wirelessbut no, just a switch will not help.
You have asked in the physics area, so I will try to give you a physics response and not an engineering one, as the other respondents haveThis might be interesting to you in terms of 'thinking out of the (engineering) box' There is a fundamental difference between voltage and currentVoltage is energy, current is matterYou can have a voltage across any interval, any distanceThere does not have to be any material connection, everCurrent is about moving material particles: usually moving electrons We know that when material particles move, excepting at the quantum level, energy gets dissipatedAnd while electron flow does have some quantum characteristics, it is fundamentally a macro effectYou do not have to consider quantum effects for what we consider to be 'practical' electrical currents Since we know that power is a factor of voltage times power, we can be confident that the higher the current, the higher the loss of powerIn fact, since power is moving across a surface, a cross section, we know that the power loss will be related to the current squaredSince voltage is not related to matter, voltage of itself, does not imply energy loss And of course, the only real energy loss you can have with transmission lines is a conversion of electrical eneryg to thermal energy.
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Power P iV Iv P; as you can see, we transmit the same P with low current i and high voltage V, and with high current I and low voltageBut, this is important, heat losses (qe and QE) are proportional to the square of the currentThus, qe ~ i^2 and QE ~ I^2 so there is less heating in the transmission wires for the low current, high voltage combinationANS A).
There is always some loss due to resistance in the transmission lineThis loss is computed using the formula P I^2 R At high voltage the current is low for a given amount of power, so the loss is less at high voltage than at low voltage.

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