if steel is heated from room temperature (20c) to (500c) what would be the change in density?coefficient for linear expansion of steel 12x10^-6 k density of steel 7800 kg
First you have to convert the coefficient of linear expansion to a coefficient of volumetric expansion. Multiply the coefficient of linear expansion by 3: Coefficient of expansion of steel,β:12E-6/°K x 3 = 36E-6/°K Difference in temperature: 480°K ΔV = VoβΔT ΔV = Vo x (0.000036) x 480 ΔV = 1m? x 0.017 ΔV = 0.017m? Originally, the steel was at 7800 kg/m? Now, the steel was at 7800 kg/ 1.017m?, or 7670 kg/m? Change in density = 7670 - 7800 = -130kg/m?
