The force, P, on a horizontal bar is 2,700 N on the bar, which has a diameter, d, of 8 mm. A. determine the normal stress on any cross section, a-a, perpendicular to the longitudinal axis of the bar.B. if the bar is made of copper, what will be the normal strain on the bar?
Solution: A) for normal stress: A (pi/4)(d^2) A (3.1416/4)(0.008 m)^2 A 6.28 x 10^-3 m^2 normal stress P/A normal stress (2,700 N)/(6.28 x 10^-3 m^2) normal stress 429,717.34 N 429.72 KN B) for normal strain: E (copper) ranges from 110 GPa to 128 GPa. For bulk modulus, it is the 128 GPa. normal strain (normal stress)/E normal strain (4.29 x 10^-4 GPa)/128 GPa normal strain 3.35 x 10^-6
