There is a 90 extrusion machine, used in the production of communication cables (outside the cable core is extruded with a layer of LLDPE), now is the configuration of Y2-280M-490KW167A inverter type ACS510197A + ABB), General Motors now found low speed when the current is too large, what reason? How to solve? The details are as follows: used for communication cable production HYA30*2*0.4, 1, line speed is 50 m / min, inverter display frequency 35.3HZ current: 116A; 2, line speed is 40 m / min, inverter display frequency of 28.2hz, current: 140A3, line speed is 35 m / min, the frequency converter significantly method: 157A 24.6HZ frequency current, because the product variety and technical reasons, we need to be in the frequency of 10HZ production. Now, it seems that if I reduce the speed again, the current will probably exceed the rated current. What should I do? Is the motor changed to frequency conversion motor? Or inverter? How to solve? Please heroes pointing, thank you!
Fan, water pump at low speed, torque is not enough, resulting in high current, if vector control can be ideal.
The extruder is a constant torque load. The original configuration is usually a DC governor + DC motor. When using a DC motor, the current is usually constant during the speed rise.
Yes, the load characteristics and control characteristics are also to be matched. Otherwise, it will be very inappropriate and lead to abnormal phenomena.
See the ACS510 manual, this type of inverter used in fan pump type, 2605 control methods of determining its U/F, the default value is 2 (the square type, namely fan pump type); for constant torque load, should be set to 1 (linear). When not available, does the debugger not modify the parameter to 1? If that's the case, will the top floor say what happened?
