In a hydraulic lift, the diameters of the pistons are 4.95 cm and 20.3 cm. A car weighing W 10 kN is to be lifted by the force of the large piston. (a) What force Fa must be applied to the small piston? (b) When the small piston is pushed in by 10.4 cm, how far is the car lifted? (c) Find the mechanical advantage of the lift, which is the ratio W/Fa.
i do no longer think of this is actual. the way it replaced into defined to me is that the evangelical christians would be caught up for the period of the rapture, and then every physique else will bypass for the period of the tribulation of the anti-christ. people who turn to Jesus are then saved yet martyred for being believers.
Yes he will Revelation 19.He is also a judge and will judge mankind
The Christian Messiah next coming is to conquer. Many people will die before that happens, but that is all part of God's wrath. God bless
a), b),c): The answer to all is the ratio of the square of the piston diameters or its inverse: Let 4.95?/20.3? Rthen a) Fa R*W b) L 10.4*R c) MA 1/R
