Am going to heat a one type of liquid (S.G of liquid is 1.2) via heat exchanger the inlet water is 98deg.c and the liquid gain 15 deg.c. what is the out let temperature of water?Note:- We don't know the inlet temperature of liquid.
Convection is warmth pass via circulating currents of air as in 'THERMALS' in the ambience. Heated air has a decrease density than cool air and consequently rises. Cooler air strikes in under the starting to be heat air and circulatory currents are set up. Thermals are used via carry close-gliders and Para-gliders to learn elevate. Convection is likewise utilized in area heating as in the abode. Radiation is with the help of rays of direct warmth as from the sunlight or an open hearth. Radiation is the only form of warmth pass that would bypass by using a vacuum.
The heat exchanger is a counter-current exchanger. Liquid in (T) ------>[ ]------> Liquid out (T + 15) Water Out <--------[ ]<------ Water in (98 deg C) (? deg C) To solve that problem, we should know the Temperature difference between the Liquid and Water at the inlet and outlet point. If the temperature of liquid at its outlet is assumed to be the same with the water entering the exchanger, then the Liquid leaving the exchanger at 98 deg C. Because 98 deg C = T + 15, then T = 83 deg C.
