Don't understand this one at all, any help would be appreciated :)1) A heat exchanger is needed to heat a process stream from 300 degrees F to 425 degrees F. The heat will be supplied by steam on the shell side of the heat exchanger. Saturated steam is available at 600 psig ( approx. 490 degrees F, and delta H vap,600psig = 1699 kJ/kg). The heat capacity of the process stream is 3.0 kJ/kg degree C. The process stream flows at a rate of 10 kg/s. The overall heat-transfer coefficient is approx. 150 btu/hr ft squared degrees F.a) what flow rate of steam (mass/time) is needed for this heat exchanger?b) The boiling point of water with which we are most familiar with is 100 degrees C. How is it possible to have saturated steam at 490 degrees F?c) Estimate the required area of the heat exchanger in feet squared?will choose best answer as always!
a] Do an energy balance. MCdeltaT on the process stream = condensation heat of the steam Take as basis 1 second MCdeltaT on the process stream = 10 x 3 x 125 x5/9 = 2083 kJ 2083/1699 = 1.226 kg steam per second b] Pressure is not atmospheric. c] Q' = U A deltaT A = Q'/U DeltaT You are going to need to convert some units first
