A 41.0-mH inductor, with internal resistance of 34.5 Ω, is connected to an ac source(t) (288 V) sin [(382 rad/s)t] (a) What is the impedance of the inductor in the circuit?answer in Ω 39.7 (got it wrong)(b) What are the peak and rms voltages across the inductor (including the internal resistance)?peak voltage: answer in V 292 (got it wrong)rms voltage: answer in V 206 (got it wrong) (c) What is the peak current in the circuit?answer in A 7.35 (got it wrong)(d) What is the average power dissipated in the circuit?answer in W 986 (got it wrong)i keep getting all this wrong what are the correct answer and what is it that i am doing wrongplease help me out with this question.plz.10pts best answer thank you! :)
Assuming that the voltage source is right, i.e., has 0 sequence impedance, and there are not the different elelements in the circuit, the present in the process the inductor would be V / Z? the place V is the voltage of the source, it particularly is likewise the voltage around the burden inductor, and Z? is the impedance of the inductor, with Z? Rs + j?L, the place Rs is the equivalent sequence resistance of the inductor, which in this occasion is negligible, ? is the angular frequency of the excitation, it particularly is 2? circumstances the utilising frequency f, and L is the inductance. The j is obviously the crucial root of -a million. Neglecting the resistive element, the value of the present will consequently be V / (2?fL) If fo is the unique frequency and Lo the unique inductance, the present after the alterations in frequency and inductance would be V / [2?(4fo)(Lo/8)] V / [2?foLo*(4/8)] 2 V / (2?foLo) so the present will boost via a element of two.
Given L41.0mH, R34.5Ω v(t) 288sin(382t) Asin(ωt) So we know ω382 rad/s and A288 V (a) Z R+jωL |Z| √((R)?+(ωL)?) (b) Vpk A Vrms A/√2 (c) Ipk Vpk/|Z| (d) Pavg (Vrms)?/|Z|
