In a hydraulic lift, the radii of the pistons are 2.02 cm and 9.6 cm. A car weighing W 11.5 kN is to be lifted by the force of the large piston. (a) What force Fa must be applied to the small piston?answer in N(b) When the small piston is pushed in by 9.8 cm, how far is the car lifted?answer in mmplease help me out i dont get it.it would be greatly appreciated if anyone can answer this for me thanks :)(c) Find the mechanical advantage of the lift, which is the ratio W / Fa.
a) The ratio of the forces is inversely proportional to the areas of the 2 pistons. Area is proportional to radius squared. The Force-ratio for small:large piston (9.6 / 2.02)^2 22.6 Force applied to small piston (11.5 / 22.6) 0.508 kN b) Distance-ratio 22.6 also. Distance car is lifted (98 mm / 22.6) 4.34 mm c) Mechanical advantage is defined as the ratio of output:input forces. Mechanical advantage 22.6 . .
a) The ratio of the forces is inversely proportional to the areas of the 2 pistons. Area is proportional to radius squared. The Force-ratio for small:large piston (9.6 / 2.02)^2 22.6 Force applied to small piston (11.5 / 22.6) 0.508 kN b) Distance-ratio 22.6 also. Distance car is lifted (98 mm / 22.6) 4.34 mm c) Mechanical advantage is defined as the ratio of output:input forces. Mechanical advantage 22.6 . .
You can BUT I really do NOT suggest it. there is different technologies and grips and etc. involved that is different and special for each and every sport
You can BUT I really do NOT suggest it. there is different technologies and grips and etc. involved that is different and special for each and every sport
