I do not understand this problemHow do I solve it?? Thanks.1You have a sample of Aluminum that weights 25.0 pounds, and you roll it into a sheet with the dimensions: 3.45 feet and 18.5 inches.A) What is the thickness of this sheet?B) If you then press the sheet a second time until the thickness is 0.00115 inches, what is the area of the new sheet?C) What will be the dimensions (in feet) of the new sheet if it was a perfect square?D) If a roll of aluminun foil measures 1.00 ft by 75 ft., how many rolls of aluminun foil may be manufactured by the 25 pounds of aluminum?Thanks?! :)
All you need to solve those question are the density of aluminumd2.7g/cm30.09754lb/in3 A)you need the area (A) of the sheet to find the thickness (t) dm/Vm/(At) tm/(dA)25lb/(0.09754lb/in3 (41.4in18.4in))0.335in B)Am/(dt)222874in2 C)dimensionsqrt(A)472in39.33feet D)This depends on the thickness of the aluminum foilIf it's 0.00115in then the volume of 1 roll V1f75f0.00115in12.42in3 The volume occupied by 25 lb of Al is: Vm/d256.3in3 so you could make 256.3/12.4220.6 rolls out of 25lb
