Consider the following statements:(1) The current in the inductor cannot change suddenly.(2) The voltage across a capacitor cannot change suddenly.Now, my confusion is in the following question.
Your picture just didn't come across on my system, so your question is a bit confusing. Yes, the properties of inductance and capacitance are almost exactly opposite each other, The important factor is TIME. FIRST, think in DC voltage mode. With a capacitor, if you present a sudden change of voltage across it, it appears as a short circuit -- but only for a short period of time. as the capacitor charges the resistance increases, until it presents an infinite resistance. The inductor, on the other hand respond oppositely. If you present a sudden change in voltage across an inductor, it present an open circuit -- but only for a short period of time. As the inductor charges it eventually presents no resistance to the voltage. NOW think in teh AC mode TIME is related to FREQUENCY. If your place an inductor and a capacitor in parallel with each other, you will develop what is known as a TUNED CIRCUIT. You will soon learn the formulas for what frequency is effected, given a capacitor and an inductor. IF you place a tuned circuit in the positive feedback loop of an amplifier, you will make what is know as an OSCILLATOR. This forms the basics of a radio or television system. The tuning of the circuit determines what channel you receive.
At t0, the capacitor acts like a short circuit. Therefore, all the current will flow through it. Then, at t 0+, the inductor current will be zero. Current source: L[2]2/s ; Resistor: L[1]1 ; Inductor: L[1]s ; Capacitor: L[1]1/s The current flowing through the inductor (2/s) * [(s+1) * (1/s)]/(s +1 + 1/s) 2/[s * (s^2 + s + 1)] (A/s) + [(B*s + C)/(s^2 + s + 1)] A*s^2 + A*s + A + B*s^2 + C*s (A+B)*s^2 + (A+C)*s +A 2 A 2 ; B -2 ; C -2 The current flowing through the inductor (2/s) + [(-2*s - 2)/(s^2 + s + 1)] (2/s) + 2*[(s + 0.5)/((s + 0.5)^2 + sqrt(0.75)^2)] + [1/sqrt(0.75)]*[sqrt(0.75) / ( (s + 0.5)^2 + sqrt(0.75)^2) )] The current flowing through the inductor i(t) i(t) 2 - 2*exp(-0.5*t)*cos[sqrt(0.75)*t] – [1/sqrt(0.75)]*exp(-0.5*t) * sin[sqrt(0.75)*t] i(0+) 2 -2 + 0 0 A ; Note that, cos0 1, sin0 0, exp(0) 1
