An electroplating unit used for obtaining aluminum for Al2O3 draws 1.0 ampere of current at a power requirement of 0.29 kilowatt hours per dayIf the unit produces 8.0 g of aluminum per day, what is the cost of producing the aluminum for a can weighing 10.0 g at 5 cents per kilowatt hour?
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Givens: - 10.0 g of aluminum Conversions: - 8.0 g aluminum / day - 0.29 kWh / day - 5 cents / kWh ?Useless info: - Draws 1.0 ampere of current I would suggest using dimensional analysis to find what order of operations You have 10 g Al can - given 8.0 g of Al / day - have days needed You have days - given 0.29 kWh / day - have kWh You have kWh - given 5 cents / kWh cost Now that you have the order of calculations, line them up (make sure your units cancel) ( 10.0 g Al ) (1 day / 8.0 g) (0.29 kWh / day) ($0.05 / 1 kWh) $0.018125 Round to 2 significant digits (all multiplication; take the lowest SD) and you should get $0.018 for a can Please double check my math and processes, and hope it helped!
