I have a DC current transformer and it is a 2500:1. I do not know what this means but I have a rectifier hooked up to it and am measuring the output DC voltage. I have hooked up resistors in values of 20Ω, 2kΩ, 10kΩ, and 20kΩ. I do not know how to convert to amperes though the resulting DC volts. How can this be done?
Your current transformer at 2500:1 means, 2500 amp flowing through bar primary, (Which passes through the centre of the coil) will produce 1 amp in the coil, but it will not be DC. The CT will have a VA rating. You would have to put 2500 amps through bar primary to achieve 1 amp on secondary winding. This is in the power generation/distribution sector. It's what is says on the tin, A current transformer. The voltage output would be minimal. To find this, you would need to measure the AC voltage at 2500 amp through bar primary, or find the number of turns on the coil and/or the voltage drop on the primary bar as it passes through the coil. Primary volts per turn Sec volts per turn.
NO such thing as a DC transformer. Do you mean an AC voltage transformer with rectifiers on the output? But ohms law should apply. Current voltage divided by resistance.
When I say voltage I mean AC voltage. When I say current, I mean AC current. Let the input voltage you apply to the primary (the 2500 side) of the transformer Vin. Let the open circuit output voltage (no load across the secondary) of the secondary (the 1 side) of the transformer Voc +++ A certain magnetizing current, lets call it Im will flow in the primary at no load. The primary winding of your transformer has a resistance, lets call it Rp. The secondary winding of your transformer has a resistance, lets call it Rs. With no power applied, if you have the equipment you can measure Rp and/or Rs. If you have the equipment, if you do not apply a load to the secondary you can apply Vin to the primary and measure Im. Due to the magnetizing current, there is a voltage drop across ip of Im*Rp volts. Because of the voltage drop, if you apply an input voltage Vin to the primary the open circuit voltage can be calculated as Voc [Vin - (Im*Rp)]*(1/2500). +++ If you apply a load to the secondary winding, lets call the current drawn by the load Is. Because of the transformer action, the output current will be reflected into the primary. Lets call the reflected output current Ips. Then Ips (1/2500)*Is. Now there will be voltage drops in the primary due both to Im and Ips, so NEGLECTING THE EFFECT OF THE RESISTANCE OF THE SECONDARY the secondary voltage is given by Vo (1/2500)*(Vin - [Rp*(Ips+Im)]) But there will be a voltage drop in the secondary. So the actual Vo, NEGLECTING NOTHING is given by Vo (1/2500)*{Vin - [Rp*(Ips+Im)]} - Is*Rs}.
