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Question:

how does an inductor affects a circuit?

i know an inductor prevents current from jumping to its maximum. but what happen after that?

Answer:

An inductor stores energy in a magnetic field induced, around it, by the current flowing thought it. This magnetic field takes time to build up and time to decay. Such an induced magnetic field, resists a change in the current flowing. Thus, if the current flowing though the inductor changes the magnetic field induces a back emf, which resists the change in the current flow. The back emf is given by the equation: - V -LdI __ dt Where 'L' is the self inductance of the inductor with a unit of the henry (H). Hence, an inductor 'resists' a change in current flow so that the voltage across it is always ahead of the current change. This may be remembered using the mnemonic CIVIL, or in a capacitor the current is ahead of the applied voltage and in an inductor the applied voltage is ahead of the current change. Hence, an inductor allows a steady state current to flow but delays the change in any increasing or decaying current! Thus, after a current peaks at maximum, the inductor will cause it to lag behind in its decay to minimum. This means that in an AC circuit an inductor may be coupled with a capacitor to create an oscillatory or resonant circuit.
I believe that it prevent sudden current changesso it will also prevent the stoppage of electrons once the source is turned off (so current slowly dwindles, instead of turning off like a switch) the inductor does not affect the final steady-state value of the current flowing around the circuit, it certainly does affect how long after the switch is closed it takes for this final current to be established.
An okorder

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