Question:
How far must the small piston be pushed down to raise the car a distance of 1.9 cm?
A hydraulic lift is lifting a car that weighs 15 kN. The area of the piston supporting the car is A, the area of the other piston is a, and the ratio A/a is 104.7. How far must the small piston be pushed down to raise the car a distance of 1.9 cm? [Hint: Consider the work to be done.]Please help, I can not figure this out. thank you
Answer:
No, an electric blanket is a serious fire hazard. My aunt got a new electric blanket for Christmas last year and it caught her bed on fire. Very dangerous.
family members have had electric blankets for years and not one incident. there are faulty blankets as in everything, but I trust them. just like christmas lights, they last for years. many times the reason for the problems are caused because the cord is damaged or something to that effect.
My hubby might kill me if I positioned a warm water bottle interior an identical mattress as an electric blanket, if i did not electricute myself first that's! he's lots greater useful than any gadget, he's often purely the suitable temperature to snuggle as much as!
(a) by employing P F1 / A1 F2 / A 246g/(1435 x 10^-4) F2/(80 3 x 10^-4) F2 14.23 kg or 139.40 4 N (b) by employing V A1 x L1 A2 x L2 1435 x 10^-4 x 0.15 80 3 x 10^-4 x L2 L2 2.fifty 9 m
Assuming no losses, the work in WE fD Fd WE the work out. Then D d(F/d) d(A/a) d 104.7 1.9*104.7 ? cm the distance the small piston must move to raise the car 1.9 cm. You can do the math. Work is force X distance for the small piston (fD) and for the big (Fd). Invoking Pascal's law, we know the pressure P is the same in the two pistons. So F PA and f Pa are true. With this physics we easily derive D d(A/a) and A/a was given as 104.7 and d is the 1.9 cm the car must be lifted.
My hubby might kill me if I positioned a warm water bottle interior an identical mattress as an electric blanket, if i did not electricute myself first that's! he's lots greater useful than any gadget, he's often purely the suitable temperature to snuggle as much as!
(a) by employing P F1 / A1 F2 / A 246g/(1435 x 10^-4) F2/(80 3 x 10^-4) F2 14.23 kg or 139.40 4 N (b) by employing V A1 x L1 A2 x L2 1435 x 10^-4 x 0.15 80 3 x 10^-4 x L2 L2 2.fifty 9 m
Assuming no losses, the work in WE fD Fd WE the work out. Then D d(F/d) d(A/a) d 104.7 1.9*104.7 ? cm the distance the small piston must move to raise the car 1.9 cm. You can do the math. Work is force X distance for the small piston (fD) and for the big (Fd). Invoking Pascal's law, we know the pressure P is the same in the two pistons. So F PA and f Pa are true. With this physics we easily derive D d(A/a) and A/a was given as 104.7 and d is the 1.9 cm the car must be lifted.
No, an electric blanket is a serious fire hazard. My aunt got a new electric blanket for Christmas last year and it caught her bed on fire. Very dangerous.
family members have had electric blankets for years and not one incident. there are faulty blankets as in everything, but I trust them. just like christmas lights, they last for years. many times the reason for the problems are caused because the cord is damaged or something to that effect.
