if u have lithum ion cell with a voltage 3.7 and capacity of 2.6ah how many cells do u need to make a battery pack for 14.8 volts , and whats the capacity of it The answer is 8 cells!!!!! and 5.2ah can some one explain why it is not 4 cells and at 10.4 ah
In your question you left out that a 5.2 ampere hours capacity is required. Also having the batteries in series adds 3.7 volts for each battery. However, a series connection does not add ampere hours. Ampere hours would add when batteries in parallel, but voltage would not.
a completely charged battery ought to have over 12.4 volts. If any cellular is undesirable, you will no longer have the potential to totally can charge it. in actuality it won't crank the starter and you will no longer have the potential to bounce start up it. A battery with a dull cellular demands changing. with the aid of lifeless, we recommend the grid interior the cellular has melted or has another irregularities. There are some battery fix shops who can replace the lifeless cellular. different than that, your suitable wager is to change the battery with the comparable team variety you have.
3.7V(2.6Ah) 3.7*2.6 9.62 [Wh]. Series four[V] 3.7*4 14.8[V]. Total power of 4 series is 9.62 * 4 38.48 [Wh]. Ah is 38.48/14.8 2.6[Ah]. Ah that is identical to unit. Parallel to increase the Ah. And to what did series four parallel two sets 14.8[V] 5.2[Ah]. The easiest way is to calculate the total power.
