In the equation:4Al+3O2 -gt;2al203When 0.590 aluminum is reacted in a closed container with 7.80 oxygen, how many grams of aluminum oxide can form?
This is also kind of a chemistry question and therefore the math people will not be able to help you What you need to do is get out your periodic table of the elements and find out how many atoms of aluminum (AL) and Oxygen (O) are in one gramm by looking at the specific weight When you have found that out you need to multiply the amount of atoms per gramm with the given measures of aluminum and oxygen to find out how many atoms of each you have avaible Next you need to divid the amount of atoms of aluminum by 4 and the amount of atoms of oxygen by 6 (since you need 4 Al and 6 O atoms for the reaction)This numbers need to be rounded down and compared to each otherIf they are not the same then take the smaller number of both, which represents you with the amount of reaction that can take place Now you need to find out how much one 2Al2O3 molecule weighs (with the help of the periodic system) and multiply it with the number of reaction that you calculated Sorry, but that is best I can doMy chemistry is almost gone by now Cheers!
