How many iron atoms are in 2.500 g of iron (III) phosphate?
Iron(III) Phosphate has the equation FePO4, meaning that there is one iron atom per molecule. Iron(III) Phosphate has a molar mass of 150.82amu. Therefore the number of moles of FePO4 is given by: number of moles mass of sample / molar mass 2.5g / 150.82amu 0.01658 moles of FePO4 Since there is 1 Fe atom per molecule, there must be 0.01658 moles of Fe atoms To calculate the actual number of atoms (as opposed to the number of moles of atoms) you use the calculation: number of atoms number of moles x avagadro's number 0.01658 x (6.022 x 10^23) 9.98 x 10^21 atoms There are 9.98 x 10^21 atoms in 2.5g of FePO4
Iron(III) Phosphate has the equation FePO4, meaning that there is one iron atom per molecule. Iron(III) Phosphate has a molar mass of 150.82amu. Therefore the number of moles of FePO4 is given by: number of moles mass of sample / molar mass 2.5g / 150.82amu 0.01658 moles of FePO4 Since there is 1 Fe atom per molecule, there must be 0.01658 moles of Fe atoms To calculate the actual number of atoms (as opposed to the number of moles of atoms) you use the calculation: number of atoms number of moles x avagadro's number 0.01658 x (6.022 x 10^23) 9.98 x 10^21 atoms There are 9.98 x 10^21 atoms in 2.5g of FePO4
Iron(III) Phosphate has the equation FePO4, meaning that there is one iron atom per molecule. Iron(III) Phosphate has a molar mass of 150.82amu. Therefore the number of moles of FePO4 is given by: number of moles mass of sample / molar mass 2.5g / 150.82amu 0.01658 moles of FePO4 Since there is 1 Fe atom per molecule, there must be 0.01658 moles of Fe atoms To calculate the actual number of atoms (as opposed to the number of moles of atoms) you use the calculation: number of atoms number of moles x avagadro's number 0.01658 x (6.022 x 10^23) 9.98 x 10^21 atoms There are 9.98 x 10^21 atoms in 2.5g of FePO4
