How many mL of 6 M H2SO4 are required to supply sulfate ion in the alum formed from 1.1 g of aluminum?
I've done all sorts of tests on this topic and am using a polishing kit that was meant for plastic, but on aluminum, but after all the pads coarse to fine (wet) I found that it's better to use the last pad again but dry, rather than using the while liquid paste they proposePolishing dry or wet makes a difference, and polishing Al is not the same as polishing a plasticIt's a tricky recipe, you can dull your Al easily, and I never got it shiny like a mirror so I want to see other answrs
alum is KAl(SO4)2.12H2O each mole has 1 mole of Al 2 moles of (SO4)-2 use molar mass to find moles of Al: 1.1 g Al 27 g/mol 0.0407 moles of Al at that 1 mole of Al to 2 moles of (SO4)-2 0.0407 moles of Al requires 0.0814 moles of (SO4)-2 find volume 0.0814 moles of (SO4)-2 6 moles / Litre KOH 0.0136 litres of H2SO4 aka 13.6 ml of 6 Molar H2SO4 your answer, rounded to 2 sig fig as was in your 1.1 g of Al, would be 14 ml of H2SO4 however, since the 6M H2SO4 has only 1 sig fig, you might be expected to round your answer off even more but I rather doubt it
