If you had excess aluminum, how many moles of aluminum chloride could be produced from 16.0g of chlorine gas, Cl2?Express your answer to three significant figures and include the appropriate units.I got .096 mol but that's incorrect
Aluminium is trivalent , so 2Al + 3Cl2--- 2AlCl3 molar mass of Cl2 is 35.45 *2=70.9 16g correspond to 16/70.9=0.226moles of Cl2 you see that 3 moles of Cl2 gives 2 moles of AlCl3 so you obtain 0.226*2/3 =0.150 moles of aluminium chloride
overall idea is to first find the moles of 16g of Cl2 then multiply that with the number of moles of the desired product
