I have an 8'2 rod solidly affixed into the wall at each end with a single bracket in the middle that is rated for 500 lbs. per pair (250 lbs. per single bracket?) Since some of the weight would be borne by the wall at each end, how much weight would it actually take to bend the bracket in the middle? (The rod is a 1/3/8' hardwood). Please show calculations! Thanks!
There is some information missing here. We still don't know how much the rod can take at the center without the bracket installed. It very much depends on the type of wood you used as well. I can give you a rough estimate based on the dimentions you provided: the rod alone should be able to handle somewhere between 10lb to 20lb at the center. Going with the minimum to be safe, with one braket at the center it can go up to 260lb load righ at the center. If you secure your rod ends at the wall, it takes more load at the wall. But lets go with the same 260lb. You have three points so the maximum distributed load you can take is 780lb over the rod. The load can be concentrated close to the bracket or the walls, but I wouldn't concentrate the load between the braket and walls. Hope this helps.
Hey, If you need some direction here what I think you have to do for your calculations You have a statically indeterminate structure. What u need to do is find the reactions at the wall (both moment and forces) and the force the middle bracket would take under a applied load P, in the middle. Once you have a expression for the force P that the middle bracket takes, you need to see how it will fail. In this configuration, if I read your question properly, it will buckle if aligned vertically. Edit post to tell me you need further help/ if you have further questions, and ill take a look into calculations if needed. In theory it sounds good but im sure there are a few obstacles to overcome
