Hi there, I am completely stuck on this question! Help Please!A heat exchanger has an outside diameter of 1.0M and overall length of 5.0M and is made from 20mm thick material.There are 36 refrigerant tubes, each 42mm outside diameter running the length of the heat exchanger.Calculate the weight of water held in this exchanger.Note: The density of water is 1000kg/m^3Thanks!
Volume of heat-exchanger = pi(1/2)^2 * 5 = 3.927 M^3 1-tube volume = pi(0.042/2)^2 * 5 = 0.00693 M^3 36-tubes volume = 36*0.00693 = 0.2494 M^3 Volume of water = 3.927 - 0.2494 = 3.6776 M^3 Density of water = 1000 kg/m^3 Mass of water = 3.6776 * 1000 = 3677.6 kg >=======< ANSWER
Easy one! Volume of 1 refrigerant tube (assuming thin-walled): Vol = πr^2 * 5 = π(0.021)^2 * 5 = 0.00693 m3 Volume of 36 refrigerant tubes = 0.00693 * 36 = 0.249 m3 Now calculate the volume of the heat exchanger: Vol = πr^2 * 5 = π(0.5-0.02)^2 * 5 = 3.62 m3 Total volume for water inside the heat exchanger = 3.62 - 0.249 = 3.369 m3 Therefore, mass of water inside = Volume * Density = 3.369 * 1000 = 3369kg Weight = 3369 * 10 N = 33690 N of water
The interior volume of the heat exchanger is calculated from its interior dimensions, and from that must be subtracted the volume of all the tubes Int. Vol. = pi r ^2 * L Int. Vol. = pi * 0.48^2 * 4.96 Int. Vol. = 3.59 m^3 . Vol. Tubes = N * pi * r^2 * L Vol. Tubes = 36 * pi * 0.021^2 * 4.96 Vol.Tubes = 0.247 m^3 Subtracting: 3.59 - 0.247 = 3.34 m^3 Mass = volume * density Mass = 3.34 * 1000 Mass = 3340 kg Weight = mass * g Weight = 3340 * 9.8 Weight = 32,700 N
