I am doing a project in which I am facing a problem to calculate the fuel efficiency of the excavator (runs with diesel). could you please suggest any method or any instrument which will be helpful for me. (as I mentioned I got to measure in fuel consumption in certain period of time)thanks
Dan - Check your math 3000 lb / 7 is 428 gals - 1 gal of jet fuel is a bit under 7 lbs Your math is off 18000 gals per hour x 5 hour cross country flight would 90000 gals of fuel the weight of the fuel 630,000 lbs alone (and only military air-force C5 SG Boeing 747-8, Super heavy lift air craft can take off w/ that load 747-8 has a total weight take off 987,000 (that includes plane - fuel - cargo pilots - every thing) Have heard that 747-8 has taken off with tw of 1,000,000 lbs (best in the world)
put a half tank of gas in it and look not were the gas needle is then add a gallon and let it run until the needle returns to half. then you have a simple math problem minutes to return to half ........... 60 minutes .............. x.......................................... gallon minutes to return to half multiplied by 1 gallon divided by 60 minutes should give you a decimal- and that how many gallons a hour if you want it to be more specific then get all the gas out to the point were theres not enough to start then add a gallon- that should be enough to get it started or leave a little in the lines to get it going and see how long it takes to die not sure how bad that is for your diesel good luck
I used to drive tractors for a living, here is what i did. Fill up the fuel tank. Write down the hour meter of the excavator. Run the excavator. Fill the fuel tank from a service tank with a flowmeter on it. Check the hour meter again. Divide the fuel used by the time ran and bingo you have fuel used per hour.
