So the mass of a shark is 2.00 x 10^4 kgSuppose a crane lifts a net with a 2.00 x 10^4 kg shark off the groundIf the new is steadily accelerated from rest over an interval of 2.5 seconds until the net reaches a speed of 1.0 m/s.How can i find the magnitude of the tension in the cable pulling the net?
First find the acceleration from the kinematic eqn vy at So a vy/t 1.0m/s/2.5^2 0.16m/s^2 Now draw a free body diagram of the shark T (tension is up) and mg (weight) is down Now write Newton's Law for this F ma So T - mg ma So T m(g + a) 2.00x10^4kg(9.80 + 0.16)m/s^2 1.99x10^5N
First find the acceleration from the kinematic eqn vy at So a vy/t 1.0m/s/2.5^2 0.16m/s^2 Now draw a free body diagram of the shark T (tension is up) and mg (weight) is down Now write Newton's Law for this F ma So T - mg ma So T m(g + a) 2.00x10^4kg(9.80 + 0.16)m/s^2 1.99x10^5N
