A hydraulic lift is lifting a car that weighs 11.3 kN. The area of the piston supporting the car is A, the area of the other piston is a, and the ratio A/a is 102. How far must the small piston be pushed down to raise the car a distance of 1.80 cm?
the liquid volume is incompressible and the liquid is sealed in the system are the assumptions we are making to solve this. when specific volume goes down in the piston with an area of a a similar amount of volume goes up in the second piston and that's the logic we are using to solve this. so V of A piston V of a piston 1.8 * A h * a h 1.8 * A/a h 1.8 * 102 cm h 183.6 cm
1,8 (cm).Aa.l A/a102 .A102a 1,8.102.al.a ./a 1,8 .102l
