PLEAS DONT GIVE ME THE ANSWER!! i just need to know how to solve:A giant excavator (used in road construction) can apply a maximum vertical force of 2.25×105 N. If it can vertically accelerate a load of dirt at 0.200 m/s2, what is the mass of that load? Ignore the mass of the excavator itself but don’t forget the weight of the load.
F-Weight (load)=mass (load)X0.2 2.25x105-9.8mass (load)=0.2mass (load)=====> mass (load)= 236.25/10=23.625kg, that weighs 231.525newtons.
Maximum force that can be applied is 2.25×10^5 N. This force makes an acceleration = 0.200 m/s2 So by using F = ma, m can be calculated. m = F/a. Rest for yourself... try it.
First draw the free body diagram of forces acting on the load. Force by excavator (upwards)= 2.25 x 105 N Weight due to gravity (downwards) = Mg (M = mass of load) As it accelerates upwards therefore net force is in upwards direction applying newton's second law of motion 2.25 x 105 - M * g = M * a ( a=0.2m/s^2) hence M = 2.25 x 105 / ( g+ a) Plug in the correct units of g and a to find the value of M.
