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Question:

In a hydraulic garage lift, the small piston has a radius of 5 cm and the large piston has a radius of 15 cm.?

What force must be applied on the small piston in order to lift a car weighing 20000N on the large piston? Could someone help me with the steps to this problem please?

Answer:

In a hydraulic Lift (F/f) (A/a) where F and f are the forces exerted by the larger and smaller pistons of cross sectional areas A and a respectively Here let the weight of car be F and we need to find f so apply the formula (Don't forget to use a uniform system of units)

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