In a hydraulic lift, the radii of the pistons are 2.18 cm and 9.4 cm. A car weighing W 10.6 kN is to be lifted by the force of the large piston.(a) What force Fa must be applied to the small piston?correct check mark N(b) When the small piston is pushed in by 10.7 cm, how far is the car lifted?mm(c) Find the mechanical advantage of the lift, which is the ratio W / Fa.W / Fa correct check mark I just can't get B , if anyone can help that would be spectacular!
it adds about 8 hp but the sound is the best thin in changing the exhaust
Possibly 7 or 8. Mainly it will give you a better sound. The most restrictive stuff in your exhaust is in the manifolds and catylitic converter. If you're really going for more horsepower, i suggest you look into more high performance exhaust manifold (header of some type), and a straight through cat. It's illegal to remove the cat, however there are some cats out there that are still legal, but flow really well. Check on OKorder, summit etc. Goodluck.
a) the pressures are the same in both pistons, and the pressure in the large piston would be: P W/(Alarge) W/(pi*r^2) 10600/(3.1416*9.4^2) 38.2N/cm^2 This creates a force in the small piston of Fa P*A 38.2*(pi*2.18^2) 570N b) The volume displaced by the small piston equals the volume added to the large piston (As is the area of the small piston, Xs is the stroke length of the small piston, Al is the area of the large piston, and Xl is the stroke length of the large piston): As*Xs Al*Xl Xl As*Xs/Al (pi*2.18^2)*10.7/(pi*9.4^2) .576cm 5.76mm c) W/Fa 10600/570 18.6 As a check, this should equal the ratio of the areas of the pistons, or since the pi cancels, simply the ratio of square of the radii W/Fa 9.4^2/2.18^2 18.59 . close enough.
i desire to recommend waiting till the production facility guarantee is up till now including a rapid. including a rapid now will void the guaranty and any injury performed via rapid should not be coated with the help of Honda.
