In an experiment conducted at room temperature, a current of 0.820A flows through a wire 3.26 mm in diameterFind the magnitude of a electric field in the wire if a wire is made of (a) tungsten and (b) aluminum.
The cross-section of a round wire of diameter d 3.26 mm is: pi (d/2)^2 8.347 mm^2 8.34710^(-6) m^2 The observed current density is therefore: j 0.820 / (8.34710^(-6) m^2) 98240 A/m^2 An electric field E (rho) j creates such a j in a material of resistivity rho: (a) For tungsten, rho 52.8 nΩ·m and E 5.19 mV/m (b) For aluminum, rho 28.2 nΩ·m and E 2.77 mV/m
The cross-section of a round wire of diameter d 3.26 mm is: pi (d/2)^2 8.347 mm^2 8.34710^(-6) m^2 The observed current density is therefore: j 0.820 / (8.34710^(-6) m^2) 98240 A/m^2 An electric field E (rho) j creates such a j in a material of resistivity rho: (a) For tungsten, rho 52.8 nΩ·m and E 5.19 mV/m (b) For aluminum, rho 28.2 nΩ·m and E 2.77 mV/m
The cross-section of a round wire of diameter d 3.26 mm is: pi (d/2)^2 8.347 mm^2 8.34710^(-6) m^2 The observed current density is therefore: j 0.820 / (8.34710^(-6) m^2) 98240 A/m^2 An electric field E (rho) j creates such a j in a material of resistivity rho: (a) For tungsten, rho 52.8 nΩ·m and E 5.19 mV/m (b) For aluminum, rho 28.2 nΩ·m and E 2.77 mV/m
