In how many ways can five couples be seated in a row of10 chairs if no couple is separated? Explain how youarrived at your answer.
1st chair is open to anybody, so 10 choices. The 2nd chair is forced to be the partner, so only 1 choice. The 3rd chair is therefore open to whoever is not seated already, so 8 choices. Next chair has only one choice (similar explanation to the 2nd chair). The 5th chair will have 6 choices, the 7th will have 4, and the 9th will have 2. Altogether, there are 10 * 8 * 6 * 4 * 2 arrangements = 3840 arrangements.
25 cuz thers 5 couples and they must be together so 10/2 = 5 so two per couple right? so thers one couple that can sit in five differebt ways or places on the bench or wat ever. so if theres five couples it would be 5 x 5 = 25
