how do u solve for inductor or L if u have a rlc circuit?
Yo need more info. What else do you know?
1) The reactance of a Capacitor Xc1/(2*Pi*f*C) 2) That of an Inductor is Xl2*Pi*f*L In your case f1.9060 Hz, this is at resonance. First calculate Xc, you have the values of f and C, Pi3.14. Then at resonance XlXc. Now you can calculate L. Note: In these equations, f should be in Hertz, C in Farads and L in Henrys. Convert the units first. You don't need to include the value of R. It only affects the Q of the circuit.
