A 220-mH inductor carries 350mA. How much energy must be supplied to the inductor in raising the current to 800mA?
tricky problem. do a search with search engines like google. this may help!
for an inductor the energy is given by U (1/2) L i^2 , where 'i' is the current so that increase of energy dU (1/2) x 220 x10^-3 ( 0.8^2 - 0.35^2) 0.057 J (nearly)
