An inductor 2H is connected in series with a bulb with resistance 5ohms and 9v dc power supply and a time constant of 0.4sWhat is the voltage across the light bulb after 0.5s. ??
Current (V/R)*(1 - e^(-t/T)) where t time, T time constant After 0.5 seconds I (9/5)*(1 - e^(-0.5/0.4)) Voltage current*resistance I*5 9*(1 - e^(-0.5/0.4)) Over to you and your calculator!
