I have this question in Mech engineering. If anyone could tell me HOW to answer it that would be grand. I don't want the answer I already have that, but if someone could tell me how to get the answer that would be great. ThanksQA load of mass 8 tonne is to be raised with a uniform acceleration of 1.1 m/s^2 by means of a light cable passing over a hoist drum of 2 m diameter. The drum has a mass of 1 tonne an a radius of gyration of 750 mm. Find the torque required at the drum if friction is neglected.A(87.8 KN-M)Once again it is the working I need not the answer. Thanks people
no longer likely. i'm a chemistry substantial and function a brother who's an engineering substantial. My degree has little to no longer something to do with engineering and reckoning on the educational you're taking over the chemistry section you will no longer even get into the contraptions used for chemistry on occasion. So fairly you probably ought to visit a various college by way of fact majoring in chemistry probably won't do you lots sturdy for chemical engineering.
The load is not just raising, it is accelerating also. You can add the uniform acceleration of 1.1 m/s^2 to acceleration of gravity (9.81 m/s^2). So a = 9.81 + 1.1 = 10.91 m/s^2. Force on cable = ma = 10.91m/s^2 x 8,000 kg = 87,280N Radius of drum = d/2 = 1m Torque from just the load = 87.28kN x 1m = 87.28kN-m Now find torque to accelerate the 1 tonne hoist drum T = Iα I = k^2 x m = (1000) x (0.750)^2 = 562.5 Since the drum radius = 1m, tangential acceleration at surface = 1.1 m/s^2 and α = 1.1/1 = 1.1 rad/sec T = 562.5 x 1.1 = 618.7 N-m = 0.619 kN-m Total torque = 87.28kN-m + 0.62 kN-m = 87.9kN-m Well, that's close. Go thru the numbers again to check; if you use g = 9.8 you will probably get the exact same answer. Hope this helps. Let me know if you need clarification. Bill
