in a hydraulic lift how much weight is needed to lift a car of man 1000kg given the ratio of areas of cross section of two pistons is 10pls derive solution with all the steps and pls explain the forumale alsoif u can pls explain the working of a hydraulic lift
car of man ? the mechanical advantage equals the ratio of the areas. So the lift needed is either 1000/10 100 kg or 1000?10 10000 kg
It comes down to Conservation of Energy/Work Work force * distance. The Work IN (what you do to the jack) must equal Work OUT ( what the jack does to the car). View it as 2 pistons connected by a U-tube, filled with a liquid. One piston has a surface area 10 times as big as the other piston. Volume area * distance a piston moves. So, if the little piston is 1 m^2 and it moves down 1 m that means that the big piston must move up enough to make room for 1m^3 of liquid. For the big piston: 1 m^3 10 m^2 * d d 0.1 m The little piston goes down 1 m and the big piston goes up 0.1 m. And both pistons must do the same Work Work little piston Work big piston Push the little piston down with a force of 100 N for 1 m, how much force must the big piston lift with? 100 N * 1 m ? N * 0.1m ? N 100 N*m / 0.1 1000 N Now the easy calculation is: Force IN * Area ratio Force OUT 100 N * 10 1000 N OUT
