I‘m stuck on this one question the answer‘s supposed to be 230m, but I can‘t get it. :SA motorcycle travelling at 100km/h on a flat road applies the brakes at 0.80m/s^2 for 1.0 min. How far did the motorcycle travel during this time?
Use the standard equation for distance with initial velocity and constant acceleration d v0t + (1/2)a t^2 in this case v0 100 km/hr 100*1000/3600 meters/second a -0.8 meters/second (negative since slowing down) t 1.0 min. 60 sec. d (100*1000/3600)*60 - (1/2)*0.8*60^2 226.667 m
The motorcycle is traveling at 27.77778 m/s. If he decelerates at 0.8 m/s^2, he will be stopped in 34.72 seconds. The rest of the minute he has his brakes applied while motionless. He travels 482.25 meters in that time. If we ignore the 0.80m/s^2, and figure him to stop in 60 seconds, he has traveled even further. Are the numbers right in the question? Edit: If the deceleration were active (some type of thruster), the position would be as follows: (being able to display a table would be nice) 00 9217.6 18370.4 27458.4 34482.04 34.72482.25 35482.22 36481.6 45440 60226.67 Applying brakes the negative acceleration would stop when the velocity reached 0.
