Question:
Physics help finding the force applied to an object, how far it is lifted and mechanical advantage?
In a hydraulic lift, the radii of the pistons are 2.76 cm and 10.8 cm. A car weighing W 8.6 kN is to be lifted by the force of the large piston. (a) What force Fa must be applied to the small piston? in N(b) When the small piston is pushed in by 9.2 cm, how far is the car lifted? in mm(c) Find the mechanical advantage of the lift, which is the ratio W / Fa.
Answer:
there is errors in framing of the question. The assertion “The device that exerts a 300N rigidity to enhance a 1300 N merchandise” is erroneous. genuinely:- The device exerts a rigidity of 1300 N while we be conscious purely a rigidity of 300N. consequently, a 300 N rigidity is bigger to 1300N rigidity. 4.33 x 3 hundred is 1300. for this reason the income of utilising this device is, ‘A given rigidity is bigger by utilising 4.33 cases’. The mechanical income is 4.33.
Get a re-built it is less labor intensive. if you don't know where to go,contact me I will help you, i know a few companies that offer a 3 year 75,000 to 100,000 mile warranty.
get rid of it if is a fmx there not very reliable a c4 will be cheaper to rebuild and last a lot longer
there is errors in framing of the question. The assertion “The device that exerts a 300N rigidity to enhance a 1300 N merchandise” is erroneous. genuinely:- The device exerts a rigidity of 1300 N while we be conscious purely a rigidity of 300N. consequently, a 300 N rigidity is bigger to 1300N rigidity. 4.33 x 3 hundred is 1300. for this reason the income of utilising this device is, ‘A given rigidity is bigger by utilising 4.33 cases’. The mechanical income is 4.33.
a) From Pascal's law the pressure is constant and since p F/A we have Fa/Aa F2/A2 So Fa F2*Aa/A2 8.6x10^3N*π*(0.0276m)^2/(π*(0.108m)^2) 562N b) The volume of fluid moved is constant so Aa*ha A2*h2 so h2 ha*Aa/A2 9.2cm*π*(0.0276m)^2/(π*(0.108m)^2) 0.601cm c) MA W/Fa 8600/562 15.3
I bet you its your torque converter thats dying.
Get a re-built it is less labor intensive. if you don't know where to go,contact me I will help you, i know a few companies that offer a 3 year 75,000 to 100,000 mile warranty.
get rid of it if is a fmx there not very reliable a c4 will be cheaper to rebuild and last a lot longer
I bet you its your torque converter thats dying.
a) From Pascal's law the pressure is constant and since p F/A we have Fa/Aa F2/A2 So Fa F2*Aa/A2 8.6x10^3N*π*(0.0276m)^2/(π*(0.108m)^2) 562N b) The volume of fluid moved is constant so Aa*ha A2*h2 so h2 ha*Aa/A2 9.2cm*π*(0.0276m)^2/(π*(0.108m)^2) 0.601cm c) MA W/Fa 8600/562 15.3
