1Given that the principle quantum number, n, is 2, what are the allowed values of l and m, and determine the number of atomic orbitals possible for n3.2What are two possible sets of quantum numbers to describe an electron in a 3s atomic orbital.3Determine with reasoning how many unpaired electrons are present in a ground state Aluminum atom (Z13).4How are the ground state configuratins for O, S, and Se alike? Given another element similarly related.5Calculate the corresponding wavelength of electromagnetic ratiation with a frequency equal to 3.0 x 10^-2 s^-1.6How does the energy and size of atomic orbitals vary with increases in n? Explain.
a) 12 oz (Avoirdupois) 1228.3495 g 340.2 g Density weight/volume so volume weight/density 340.2/2.7 126 mL 126 cm^3 b) Volume of a rectangular box lengthheightwidth(height for us here thickness) We know the lengthwidth 75 ft^2 1 ft 12 inches 12 inches 122.54 cm 30.48 cm 1 ft^2 30.4830.48 cm^2 929.03 cm^2 75 ft^2 75929.03 cm^2 69677 cm^2 so the lengthwidth is 69677 cm^2 volume 126 cm^3 lengthwidththickness 69677thickness 126 69677thickness thickness 126/69677 cm 1260/69677 mm 0.018 mm
1There are 4 orbitals when n2; 2s, 2px, 2py and 2pzl describes the shapeFor s orbitals, l is 0For p orbitals l is 1remember that m is defined by: -l ≤ m ≤ l so for l0 m0 the number of orbitals per shell is equal to n^2, so when n3 there are 9 orbitals23s orbital: n3 l0 m0 but spin, or s, can be plus or minus 1/2 3Aluminium atom electron config 1s2 2s2 2p6 3s2 3p1 so one unpaired electron4Don't know, too tired5wavelength frequency/speed of lightSimple now eh? 6I grow weary of thisTry here chemed.chem.purdue.edu/genchem/topicreview/bp/ch6/quantum.htmlcombo
