A grain silo has sprung a leak and the leaking grain is forming a conical pile below the silo. the grain is leaking at a rate of 0.7m^3/s. if the base width of th pile is always twice the height of the pile, how fast is the pile increasing in height when it is 2m high?
// dv/dt=0.7 dh/dt=? when x=2 v=pir^2h/3=2pix^3/3 dv/dt=2pix^2dx/dt sub and get dx/dt=0.0279, where x is the height
