A 24.0 V battery is in series with a switch, a 0.40 H inductor, time constant of 16 ms, and a 25 ohm resistor.(a) Find the potential differences across the inductor at t τ. V(1L) (b) Find the potential differences across the resistor at t τ. V(1R) (c) Find the potential differences across the inductor at t 3τ. V(2L) (d) Find the potential differences across the resistor at t 3τ. V(2R) Me and my partner are completely stuck on here, if someone could help i would be incredibly greatful!
The time constant of an inductor is L/r where the inductor is modelled by an ideal inductor L and a resistor r in series. So your inductor can be represented as 0.4H in series with a resistance of 0.6/(16*10^-3) 37.5 Ohms. the total resistance in the circuit is R 37.5 + 25 62.5 ohms, and the overall time constant is 0.4/62.5 6.4ms Now you can use the formula I V/R(1 - e^(-t/6.4*10^-3)) where V 24 to calculate the current at any time t. I am not certain what the symbol τ means in your question, so I am going to leave it to you to calculate the value of I at τ and 3τ (Iτ I3τ) Once you have these currents you can answer the questions as follow - b) with Iτ use V IR to find the voltage across the 25ohm resistor a) subtract the answer to (b) from 24v then do the same with I3τ
by ability of Ohms regulation, the Viktage throughout the time of a resistor is the present in it cases the resistance. Voltage of Resistor equals (3.0)(3.5)10.5 V. Voltage throughout the time of an inductor is the inductance cases the cost of replace of the present. Voltage of Inductor equals (2.8)(.260).728 V. including those mutually provides 11.2 V
