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Process water with a specific heat capacity of 4.182 KJ Kg-1 K -1 flows at a rate of 0.050 Kg s-1 through a...?

Process water with a specific heat capacity of 4.182 KJ Kg-1 K -1 flows at a rate of 0.050 Kg s-1 through a heat exchanger where its temperature is increased from 16C to 85C. Heat is supplied by exhaust gases (mean specific heat capacity of 1.075 KJ Kg-1 K-1) which enter the heat exchanger at a temperature of 420C. If the mass flowrate of the exhaust gases is 0.044 kg s-1, determine their outlet temperature.

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Heat taken up by water = W = 0.05 ? 4.182 ? (85-16) = 14.43 kJ/s = 14.43 kW. Let outlet temperature of exhaust gas = T The above power (= heat quantity per second) is removed from the gas, so we may write: (420-T) ? 1.075 ? 0.044 = 14.43 giving T = [(420 ? 1.075 ? 0.044) – 14.43]/(1.075 ? 0.044), i.e. T = 114.93?C.

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