An RL circuit consists of two inductors of self-inductance L1 10.00 H and L2 4.00 H connected in parallel to each other, and connected in series to a resistor of 6.00 ? and a battery of 4.00 V (See figure). Assume that the inductors have no mutual inductance. When the battery is suddenly connected what is the inital rate of change of the current in inductor L1?Figure:
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Initially no current flows in L1 or L2, so the voltage drop across R 0 and thus 4 V is applied to L1 and L2. Use the formula V LdI/dt to find dI1/dt and dI2/dt. P.S. You did a bad copy of the imageshack page URL. What you posted actually ends with just as it appears, which is not a URL. That's because you used a simple copy command (ctrl-C or whatever) instead of Copy Shortcut. I'm assuming you have R + (L1 || L2), where + means 'in series with' and || means 'in parallel with'. EDIT: OK, got your URL and it's the way I assumed it was and fits your description.
